Question

6x² + x - 1 = 0 fórmula resolutiva
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Answer 1

Resposta:

$6x^2+x-1=0$

$x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:6\left(-1\right)}}{2\cdot \:6}$

$x_{1,\:2}=\frac{-1\pm \:5}{2\cdot \:6}$

$x_1=\frac{-1+5}{2\cdot \:6},\:x_2=\frac{-1-5}{2\cdot \:6}$

$x=\frac{1}{3},\:x=-\frac{1}{2}$