Matemática, perguntado por Vixxunnie, 11 meses atrás

64. racionalize os denominadores ​

Anexos:

Soluções para a tarefa

Respondido por GeBEfte
1

a)

\frac{4}{\sqrt{15}}~.~\frac{\sqrt{15}}{\sqrt{15}}~=\\\\\\=~\frac{4~.~\sqrt{15}}{\sqrt{15}^{\,2}}\\\\\\=~\boxed{\frac{4\sqrt{15}}{15}}

b)

\frac{9}{\sqrt{6}}~.~\frac{\sqrt{6}}{\sqrt{6}}~=\\\\\\=~\frac{9~.~\sqrt{6}}{\sqrt{6}^{\,2}}\\\\\\=~\frac{9\sqrt{6}}{6}\\\\\\=~\boxed{\frac{3\sqrt{6}}{2}}

c)

\frac{6}{5\sqrt{22}}~.~\frac{\sqrt{22}}{\sqrt{22}}~=\\\\\\=~\frac{6~.~\sqrt{22}}{5\sqrt{22}^{\,2}}\\\\\\=~\frac{6\sqrt{22}}{5~.~22}\\\\\\=~\frac{6\sqrt{22}}{110}\\\\\\=~\boxed{\frac{3\sqrt{22}}{55}}

d)

\frac{8}{10+\sqrt{3}}~.~\frac{10-\sqrt{3}}{10-\sqrt{3}}~=\\\\\\=~\frac{8~.~10~-~8~.~\sqrt{3}}{10^2~-~10~.~\sqrt{3}~+~10~.~\sqrt{3}~-~\sqrt{3}^{\,2}}\\\\\\=~\frac{80-8\sqrt{3}}{100~-~10\sqrt{3}~+~10\sqrt{3}~-~3}\\\\\\=~\boxed{\frac{80-8\sqrt{3}}{97}}


Vixxunnie: obrigada
GeBEfte: Tranquilo
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