Question

48-{28-4•[9•(40÷5-3)÷(17-3•4)]} ​

Answer 1

Resposta:

=48-{28-4×[3×[40÷5-3]÷(17-3×4)]}

=48-{28-4×[3×[8-3]÷(17-12)]}

=48-{28-4×[3×[5]÷5]}

=48-{28-4×[15÷5]}

=48-{28-4×3}

=48-{28-12}

=48-{16}

=48-16

=32

Answer 2

Resposta:

56

$48 - (28 - 4.(9.(40 \div 5 - 3) \div (17 - 3.4)))= \\ 48 - (28 - 4 \times (9(8 - 3) \div (40 \div 5 - 3) \div (17 - 3 \times 4)) \\ 48 - (28 - 4 \times (9(8 - 3) \div (17 - 3 \times 4)) \\ - 3 \times 4 \\ - (3 \times 4) \\ - 12 \\ 48 - (28 - 4 \times (9(40 \div 5 - 3) \div (17 - 3 \times 4))) \\ 48 - (28 - 4 \times (9(40 \div 5 - 3) \div (17 - 12))) \\ 48 - (28 - 4 \times (9(9 \times 5 \div (17 - 12))) \\ 48 - (28 - 4 \times (9(8 - 3) \div (17 - 12))) \\ 48 - (28 - 4 \times (9 \times 5 \div 5))) \\ 48 - (28 - 4 \times (9 \times 1)) \\ 48 - (28 - 4 \times 9) \\ - 4 \times 9 \\ - (4 \times 9) \\ - 36 \\ 48 - (28 - 4 \times 9) \\ 48( - 28 - 36) \\ 28 - 36 \\ - (36 - 28) \\ - 8 \\ 48 - (28 - 36) \\ 48 - ( - 8) \\ 48 + 8 \\ 56 \\ resposta \\ 56$