Question

(4/9)^x+(2/3)^x-2=0
$(4 \9)^x + (2 \3) - 2 = 0$
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Answer 1

$( \frac{4}{9} ) {}^{x} + ( \frac{2}{3} ) {}^{x - 2} = 0$

$( \frac{4}{9} ) {}^{x} = - ( \frac{2}{3} ) {}^{x - 2}$

$\frac{( \frac{4}{9} ) {}^{x} }{( \frac{2}{3} ) {}^{x - 2} } = - 1$

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