Question

(-4)^3 + (0,2)^0 + (1,5)^1

1¹⁰ + (-3)⁰ . (-2)⁵

(-1/2)² . (-2/3)⁰ : (1/5)¹

-2³ . 5² - 4² + 10⁰

-1/5 + (2/3)² . (-1/7)²

Como resolver

Answer 1

Resposta:

Veja abaixo

Explicação passo a passo:

A:

$-4^3 = -64\\0,2^0 = 1\\1,5^ 1 = 1,5\\-64+1+1,5 = 61,5$

B:

$1^1^0 = 10\\-3^0 = 1\\-2^5 = 32\\10+1*32 = 42$

C:

$(-1/2)^2 = 1/4\\(-2/3)^0 = 1\\(1/5)^1 = 1/5\\1/4 * 1/1/5 = (1/4)/(1/5)\\(1/4)/(1/5) = 1/20$

D:

$-2^3*5^2-4^2+10^0 = -8*25-16+1\\-8*25-16+1 = -215$

E:

$-1/5 + 4/9 * 1/49 = -421/2205$