Question

32 ^2x+1 = raiz de 8

Answer 1

$32 ^{2x+1} = \sqrt{8} \\ \\ (2^5) ^{2x+1} = \sqrt{2^3} \\ \\ (2^5) ^{2x+1} = (2^3)^{ \frac{1}{2} } \\ \\(2) ^{5*(2x+1)} = (2)^{3*( \frac{1}{2}) } \\ \\ 5(2x+1)=3* \frac{1}{2} \\ \\10x+5 = \frac{3}{2}$
$\\ (10x+5)*2 = 3\\ \\20x+10 = 3\\ \\ 20x = 3-10 \\ 20x = -7\\ \\ x = \frac{-7}{20}$