Question

3 calcula o valor exacto de :

3.1 log2 32
3.2 log3 1 sobre 27
3.3 log 100
3.4 1N (e elevado 5)+41ne+1n1

Answer 1

Boa tarde Samuel 

3.1 log2(32) = log2(2^5) = 5log2(2) = 5

3.2 log3(1/27) = log3(3^-3) = -3log3(3) = -3

3.3 log(100) = log(10^2) = 2log(10) = 2