Question

(2x-3)²-4(x-1)(x-1)+5=6

Answer 1

Resposta:

$(2x-3) ^{2} -4(x-1)(x-1)+5=6\\= 2x^{2} +9-4x^{2} +4+5=6\\= 6x^{2} +18=6\\= 6x^{2} + 18 - 6=0\\= 6x^{2} +12=0\\\\Bhaskara\\A=6\\B=0\\C=12\\\\delta = b^{2} -4ac\\delta = 4 * 6*12\\delta = 288\\\\x= \frac{-b +/-\sqrt{delta} }{2a} \\x = \sqrt{288} \\x = 16.9705627485\\x=17$