Question

2 x elevado ao quadrado menos 8x mais 8 igual a zero

Answer 1

2x^2 - 8x + 8 = 0

a = 2
b = - 8
c = 8

Delta = b^2 - 4.a.c
Delta = (- 8)^2 - 4.2.8
Delta = 64 - 64
Delta = 0

x = - b +- VDelta / 2.a
x = - (- 8) +- V0 / 2.2
x = 8 +- 0 / 4

x' = 8 - 0 / 4
x' = 8 / 4
x' = 2

x" = 8 + 0 / 4
x" = 8 / 4
x" = 2

S = { 2 }

Answer 2

$2x^{2}$ - 8x + 8 = 0
Δ=$b^{2}$ - 4.a.c
Δ=$(-8)^{2}$ - 4.2.8
Δ=64-64

x=$\frac{-b + ou - \sqrt{Delta} }{2.a}$
x=$\frac{-(-8)+ ou - \sqrt{0} }{2.2}$
x=$\frac{8+ou- 0}{4}$

x'=$\frac{8+0}{4} = \frac{8}{4} = 2 x"=[tex] \frac{8-0}{4} = \frac{8}{4}$ = 2

S={2,2}