Question

2- Efetue os produtos:
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Answer 1

Não sei, ainda to no 9° ano

Answer 2

Explicação passo-a-passo:

a) $-3x.8y=-3.8.x.y=-24xy$

b) $-3ab.(-8ab)=-3.(-8).a.a.b.b=24.a^{1+1}.b^{1+1}=24a^{2}b^{2}$

c) $-7my.2my=-7.2.m.m.y.y=-14.m^{1+1}.y^{1+1}=-14m^{2}y^{2}$

d) $8ab.(-5ax)=8.(-5).a.a.b.x=-40.a^{1+1}.b.x=-40a^{2}bx$

e) $a^{2}x^{3}y.(-3ay)=-3.a^{2}.a.x^{3}.y.y=-3.a^{2+1}.x^{3}y^{1+1}=-3a^{3}x^{3}y^{2}$

f) $-3a^{3}by^{2}.(-\frac{1}{3}ab^{2}y^{2})=-3.(-\frac{1}{3}).a^{3}.a.b.b^{2}.y^{2}.y^{2}=1.a^{3+1}.b^{1+2}.y^{2+2}=a^{4}b^{3}y^{4}$

g) $-3a^{2}bc^{3}.6ab^{2}=-3.6.a^{2}.a.b.b^{2}.c^{3}=-18a^{2+1}.b^{1+2}.c^{3}=-18a^{3}b^{3}c^{3}$

h) $\frac{2}{3}b.(-\frac{1}{5}a).\frac{3}{2}ab=\frac{2}{3}.(-\frac{1}{5}).\frac{3}{2}.a.a.b.b=-\frac{1}{5}.a^{1+1}.b^{1+1}=-\frac{1}{5}a^{2}b^{2}=-\frac{a^{2}b^{2}}{5}$