Question

2. [(6+7. √9)÷ 3 elevado a 2+(21-5. √4)]
Me ajudem pfvr, preciso pra hj

Answer 1

$\large\boxed{\begin{array}{l}\underline{\rm C\acute alculos\,auxiliares:}\\\sf 2[(6+7\cdot\sqrt{9})\div3]=2\cdot[(6+7\cdot3)\div3]\\\sf=2\cdot[(6+21)\div3]\\\sf=2\cdot[27\div3]=2\cdot9=18\\\sf2+(21-5\cdot\sqrt{4})\\\sf 2+(21-5\cdot2)\\\sf=2+(21-10)=2+11=13\end{array}}$

$\large\boxed{\begin{array}{l}\sf2\cdot[(6+7\cdot\sqrt{9})\div3]^{2+(21-5\cdot\sqrt{4})}=18^{13}\checkmark\end{array}}$