Question

12.(1/2.y)-5)+y=3.y-20

(x-5).(x+5)+35=x^2-2.x+10

〖(4.x-12)〗^2=16.x^2-20.x-84
precizo resolver essas tres equacoes alguem consegue me ajudar

Answer 1

( 1/2)*y -5 + y=3*y -20       TIRANDO O MMC=2
y -10+2*y=6*y-40
3*y-10=6*y-40
3*y-6*y=-40+10
-3*y=-30  ⇒y=10


(x-5)*(x+5) +35= x^2-2*x+10
x^2-25 +35=x^2-2*X +10
x^2+10=x^2-2*x +10    
-2*x=0  ⇒x=0
 
(4*x-12)^2=16*x^2-20*x-84
16*x^2-96*x+144=16*x^2-20*x-84
-96*x+20*x=-144 -84
-76*x= -228 ⇒x=3

VALEU!!!!!