Question

1) Se log 2 = a e log 3 = b, expresse log 72 em função de a e b

Answer 1

$\log72=$

$\log(3.3.2.2.2)=$

$\log(3^2.2^3)=$

$\log3^2+\log2^3=$

$2\log 3+3\log 2=$

$2b+3a$