Question

1)Resolva as expressões

a) 29-100: 5²+3.√16

b) (17+7²) + (42:√36)

c) [28-3.elevado a 4 do lado do 3) : 9 (32 : 2-6)] - 18

d)26+{[(26-9+3) - √36 : 3+3 . 18) - 66]

Answer 1

$a)29-100:5^{2}+3* \sqrt{16}=29-(100:25)+(3*4) =29-4+12=37\\\\b)(17+7^{2})+(42: \sqrt{36} )=17+49+(42:6)=17+49+7=73$

$c)[28-3^{4}:9*(32:2-6)]-18=[28-(81:9)*(32:2-6)]-18=$
$[28-(81:9)*[(32:2)-6]]-18=[28-9*(16-6)]-18= \\28-(144-54)-18=100$

$d)26+[(26-9+3)- \sqrt{36}:3+3*18)-66 ]= \\26+[(26-9+3)-(6:3)+(3*18)]-66= \\26+[26-9+3-2+54]-66=32$

:.

Answer 2

a) $29-100\div5^2+3\cdot\sqrt{16}=29-100\div25+3\cdot4=29-4+12=37$.

b) $(17+7^2)+(42\div\sqrt{36})=17+49+42\div36=66+7=73$.

c)

$[28-3^4\div9\cdot(32\div2-6)]-18=[28-81\div9\cdot(16-6)]-18=[28-81\div9\cdot10]-18$

$[28-3^4\div9\cdot(32\div2-6)]-18=[28-9\cdot10]-18=[28-90]-18=-62-18=-80$.

d)

$26+\{[(26-9+3)-\sqrt{36}\div3+3\cdot18]-66\}=26+\{[20-6\div3+3\cdot18]-66\}$

$26+\{[(26-9+3)-\sqrt{36}\div3+3\cdot18]-66\}=26+\{20-2+54-66\}=26+6=32$