Question

(1/2) elevado a 0 × [(1/2) elevado a 3 ] elevado a -4 ÷ (1/3) elevado a 8 × (1/3) elevado a 9

me ajudem por favor!!​

Answer 1

Resposta:

(1/2)^0 × [(1/2)^3]^-4 ÷ (1/3)^8 × (1/3)^9 = 1 × (1/2)^-12 ÷ (1/3)^8 × (1/3)^9 = (1/2)^-12/(1/3)^8 × (1/3)^9 = (1/2)^-12 × (1/3)^9-8 = 2^12 × (1/3)^1 = 4096/3