03. Identifique a dízima periódica composta de acordo com os exemplos abaixo: a) 0,150483789... b) 1,125125125... c) 0,2313131... d) 0,454545...
Soluções para a tarefa
Resposta:
x
2
−14x+48=0
\mathsf{\Delta = b^2 - 4.a.c}Δ=b
2
−4.a.c
\mathsf{\Delta = (-14)^2 - 4.1.48}Δ=(−14)
2
−4.1.48
\mathsf{\Delta = 196 - 192}Δ=196−192
\mathsf{\Delta = 4}Δ=4
\begin{gathered}\mathsf{x = \dfrac{-b \pm \sqrt{\Delta}}{2a} = \dfrac{14 \pm \sqrt{4}}{2} \rightarrow \begin{cases}\mathsf{x' = \dfrac{14 + 2}{2} = \dfrac{16}{2} = 8}\\\\\mathsf{x'' = \dfrac{14 - 2}{2} = \dfrac{12}{2} = 6}\end{cases}}\end{gathered}
x=
2a
−b±
Δ
=
2
14±
4
→
⎩
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎧
x
′
=
2
14+2
=
2
16
=8
x
′′
=
2
14−2
=
2
12
=6
\boxed{\boxed{\mathsf{S = \{8;6\}}}}\leftarrow\textsf{letra A}
S={8;6}
←letra A
\mathsf{m^2 + n^2 = 8^2 + 6^2}m
2
+n
2
=8
2
+6
2
\mathsf{m^2 + n^2 = 64 + 36}m
2
+n
2
=64+36
\boxed{\boxed{\mathsf{m^2 + n^2 = 100}}}\leftarrow\textsf{letra B}
m
2
+n
2
=100
←letra B