Question

y= -x²-x+6 ajudaaaaa​

Answer 1

Resposta:

y= -x²-x+6

$-x^2-x+6=0~~~~\times(-1)\\ \\ x^2+x-6=0\\ \\ \\ a=1\\ b=1\\ c=-6\\ \\ \\ \Delta=b^2-4ac\\ \Delta=1^2-4(1)(-6)\\ \Delta=1+24\\ \\ \Delta=25\\ \\ \\ x=\dfrac{-b\pm\sqrt{\Delta} }{2a}\\ \\ \\ x=\dfrac{-1\pm\sqrt{25} }{2(1)}=\dfrac{-1\pm5}{2}$

$x'=\dfrac{-1+5}{2}=\dfrac{4}{2}=\boxed{2}\\ \\ \\ x"=\dfrac{-1-5}{2}=-\dfrac{6}{2}=\boxed{-3}$

Answer 2

Resposta:

S= {-2, 3}

Explicação passo-a-passo:

$y = - x {}^{2} - x + 6$

$- x {}^{2} - x + 6 = 0 \: \: \: \times ( - 1)$

$x {}^{2} + x - 6 = 0$

$a = 1 \: \: b = 1 \: \: \: c = - 6$

$delta = b {}^{2} - 4ac$

$delta = 1 {}^{2} - 4.1. - 6 = 1 + 24 = 25$

$\sqrt{25} = 5$

$x1 = \frac{ - 1 + 5}{2.1} = \frac{4}{2} = 2$

$x2 = \frac{ - 1 - 5}{2.1} = \frac{ - 6}{2} = - 3$