Question

(y-2).(y-2)=(3y-1) me ajudem

Answer 1

(y-2).(y-2)=(3y-1)

y^2 - 4y + 4 = 3y - 1

y^2 - 7y + 5 = 0

os coeficientes

a = 1, b = -7, c = -5

delta

d = 49 - 20 = 29

as raízes

y1 = (7 + v29)/2

y2 = (7 - v29)/2

o vértice

Vx = -b/2a = 7/2

Vy  = -d/4a = -29/4