Question

x²+x-12=15 (bhaskara)​

Answer 1

${x}^{2} + x - 12 = 15 \\ {x}^{2} + x - 12 - 15 = 0 \\ {x}^{2} + x - 27 =0 \\ delta = {b}^{2} - 4ac \\ delta = {1}^{2} - 4 \times 1 \times ( - 27) \\ delta = 1 +108 = 109 \\ delta = 109 \\ \sqrt{delta} = \sqrt{109} = aproximadamente \: 10.4 \\ x1 = \frac{ - b + \sqrt{delta} }{2 \times a} = \frac{ - 1 + 10.4}{ +2} = \frac{9.4}{2} = 4.7 \\ x2 = \frac{ - b - \sqrt{delta} }{2 \times a} = \frac{ - 1 - 10.4}{2} = \frac{ - 11.4}{2} = - 5.7$
Espero ter ajudado!!! Bons estudos!!!