Question

x²+x-12=0 como resolvo usando delta e Bhaskara?

Answer 1

x²+x-12=0

a=1 b=1 c=-12

Δ= b²-4ac

Δ= (1²) - 4 x 1 x (-12)

Δ= 49

raiz de delta = 7

x' = -b + raiz de delta

                 2 x a

x'= -1 + 7

      2 x 1

x' = 6

      2

x'= 3

x'' = -b - raiz de delta

               2 x a

x''= -1 -7

      2 x 1

x''= -8

       2

x''= -4

S= {3, -4}