Question

-x²+x+12=0 (bhaskara)

Answer 1

-x²+x+12=o

x²-x-12=0

∆=(-1)²-4×1×(-12)
∆=1+48
∆=49

X=-(-1)±√49 / 2

X= 1±7 /2

X' 1+7 /2 = 8/2 = 4

X" 1-7 /2= -6/2= -3

Answer 2

- x² + x + 12= 0                     a= - 1     b= 1   C= 12

usando fórmula bhaskara 
Delta = b² - 4.a.c
Delta=  1² - 4. (-1). 12
Delta = 49

Raízes são x'= 3 e x"= 4