Question

-x²+x+12=0
alguém pode resolver?

Answer 1

-x^2+x+12=0
delta=b^2-4ac
delta=1^2-4.(-1).12
delta=1+48
delta=49
x=-b-/+ raiz de delta/2a
x=-1-7/2.(-1)
x=-8/-2
x=4
x=-1+7/2.(-1)
x=6/-2
x=-3

Answer 2

-x2+x+12=0
-x+12=0
-x=-12
assim