Question

x2 mais 8 x menos 16 =0

Answer 1

Eq do 2º grau, aplicar Baskhara;

$x^{2} +8x-16=0$

Δ=$\sqrt{ 8^{2}-(4*1*(-16)) } \\ \\ \sqrt{64+64} \\ \\ \sqrt{128} \\ \\ \sqrt{ 2^{7} }=8 \sqrt{2}$

$x^{'} = \frac{-8+8 \sqrt{2} }{2} =-4+4 \sqrt{2} \\ \\ x^{"} = \frac{-8-8 \sqrt{2} }{2} =-4-4 \sqrt{2}$