Question

X2-9x+20=12 resolva usando bhaskara

Answer 1

x²-9x+20-12=0
x²-9x+8=0
Δ=(-9)²-4.1.8
Δ=81-32
Δ=49

x= -(-9)+-√49 sobre 2.1
x'=9+7 /2
16/2=8

x"=9-7/2
2/2=1

Answer 2

-b-+ √b²- 4.a.c/2.a
x=9-+√9² -4.1.8/2.1
x= 9-+√81-32/2
x=9-+√49/2
x=9-+7/2          x1=9+7/2=8
                       x2= 9-7/2=1