Question

x2-8x+ 10
usando fórmula de bastará

Answer 1

Olá, Genairg96.

$\Delta = (-8)^2-4\cdot1\cdot10=64-40=24=4\cdot6\\\\ x=\frac{8\pm\sqrt\Delta}2=\frac{8\pm2\sqrt6}2=4\pm\sqrt6\Rightarrow\begin{cases}x_1=4+\sqrt6\\x_2=4-\sqrt6\end{cases}$