Question

x2+6x+9=0como resolvo

Answer 1

$x^{2} +6+9=0 \Delta= b^{2} -4.a.c= \Delta= 6^{2} -4.1.9= \Delta=36-36=0$
$x1=-+6 \sqrt{0} /2=6-0/2=6/2=-3 x2=-+ \sqrt{0} /2=6+0/2=6/2$=-3

S={-3,3}

Answer 2

x²+6x+9=0

a=1  b=6  c=9

Δ=b²-4ac
Δ=(6)²-4.1.9
Δ=36-36
Δ=0                

x=-b+-√Δ   => -6+-0           x' =-6+0=-6/2=-3
       2.a             2.1                    2
                                              
                                           x''=-6-0/2=-6/2=-3