Question

-x² +6x - 5 = 0 ME AJUDEEEEEEEEEEM BHASKARA

Answer 1

-x² +6x - 5 = 0 ME AJUDEEEEEEEEEEM BHASKARA
ax² + bx + c = 0
- x² + 6x - 5 = 0
a = - 1
b = 6
c = - 5
Δ = b² - 4ac
Δ = (6)² - 4(-1)(-5)
Δ = 36 - 20
Δ = 16  -----------------> √Δ = 4  ======> √16 =4
se
Δ > 0 (DUAS raízes diferentes)
então
(baskara)

x = - b + √Δ/2a

x' = -6 + √16/2(-1)
x' = - 6 + 4/-2
x' = -2/-2
x' = + 2/2
x' = + 1
e

x" = - 6 - √16/2(-1)
x" = - 6 - 4/-2
x" = - 10/-2
x" = + 10/2
x" = 5

x' = 1
x" = 5