Question

X2-6×+8=0
A=1
B=-6
C=8

Answer 1

Resposta:

$x^{2} -6x+8=0\\ \\ coeficientes:a=1,~b=-6,~c=8\\ \\ delta=b^{2} -4.ac\\ \\ delta=(-6)^{2} -4.1.8\\ \\ delta=36-32\\ \\ delta=4$

$x=\frac{-b+-\sqrt{delta} }{2a} \\ \\ x=\frac{-(-6)+-\sqrt{4} }{2.1} \\ \\ x=\frac{6+-2}{2} \\ \\ x'=\frac{6-2}{2} =\frac{4}{2} =2\\ \\ x''=\frac{6+2}{2} =\frac{8}{2} =4\\ \\ S~~\left \{ {{2,~4} {}} \}$