Question

x2+6/4-x/4=x+6/2-5/3

Answer 1

Resposta:

S = {15 + √129/24; 15 - √129/24}

Explicação passo-a-passo:

x² + 6/4 - x/4 = x + 6/2 - 5/3

x² + 3/2 - x/4 = 3 - 5/3

x² + 3/2 - x/4 = 9 - 5/3

x² + 3/2 - x/4 = 4/3⇒mmc = 12

12x² + 18 - 3x = 12x + 16

12x² + 18 - 3x - 12x - 16 = 0

12x² + 2 - 15x = 0

12x² - 15x + 2 = 0

x = - (-15±√(-15)² - 4.12.2 / 2.12

x = 15 ± √225 - 96 / 24

x = 15 ± √129 / 24

x' = 15 + √129 / 24

x" = 15 - √129/24

Espero ter ajudado

Answer 2

Ola!!

Têm-se a equação:

${\color{blue}{x^2+\frac{6}{4}-\frac{x}{4}=x+\frac{6}{2}-\frac{5}{3}}}$

Destarte:

$x^2+\frac{-x+6}{4}=x+3-\frac{5}{3}$

$12x^2+(-3x)+18=12x+36-20$

${\color{blue}{12x^2-15x+2=0}}$

$Coeficientes: \left\{\begin{array}{cc}a=12\\b=-15\\c=2\\\end{array}\right$

Lembrando que:

$\Delta=b^2-4*a*c$

$\Delta=(-15)^2-4*12*2$

$\Delta=225-96$

$\Delta=129$

Bhaskara:

$\large\boxed{\boxed{{x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2*a}}}}}}$

$x_{1,2}=\frac{15\pm\sqrt{129}}{2*12}=\frac{15\pm\sqrt{129}}{24}$

Dúvidas??Comente!!