Question

x²+5x-6=0

tem como colocar a conta para ver se acertei?

Answer 1

Olá Angela,

Segue abaixo resolução:

 

$x^2 + 5x - 6 = 0$

$x = \frac{- b +- \sqrt{b^2 - 4*a*c}}{2a}$

$x = \frac{-5 +- \sqrt{25 + 24}}{2}$

$x = \frac{-5 +- 7}{2}$

$x' = \frac{-5 + 7}{2} = 1$

$x" = \frac{-5 - 7}{2} = -6$

 

$\boxed{x' = 1 e x" = -6}$

Answer 2

$<var>x^{2} + 5x - 6 = 0 \\\\ \Delta = b^{2} - 4ac \\ \Delta = 5^{2} - 4(1)(-6) \\ \Delta = 25 + 24 \\ \Delta = 49 \\\\ x = \frac{-b \pm \sqrt{\Delta}}{2a} \\\\ x = \frac{-5 \pm \sqrt{49}}{2*1} \\\\ x = \frac{-5 \pm 7}{2}</var>$

 

$<var>x' = \frac{-5 + 7}{2} \\ x' = \frac{2}{2} \\ \boxed{x' = 1} \\\\\\ x''= \frac{-5 - 7}{2} \\\\ x''= \frac{-12}{2} \\ \boxed{x'' = -6}</var>$