Question

x²+ 5x + 6 =0 resolva a equação

Answer 1

x²+ 5x + 6 =0

a=1 b=5 c=6

∆= b^2-4ac

∆=5^2-4.1.6

∆=25-24

∆=1

x=-b+-√∆
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2a

x=-5+-1
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2

x'= -5+1÷2
= -4 ÷2
= -2

x"= -5-1 ÷ 2
= -6÷2
= -3

Answer 2

$x^2 + 5x + 6 = 0 \\ a = 1, b = 5, c = 6 \\ \\ \Delta = b^2 - 4ac \\ \Delta = 5^2 - 4 \times 1 \times 6 \\ \Delta = 25 - 24 \\ \Delta = 1 \\ \\ x = \frac{-b \pm \sqrt{\Delta}}{2a} \\ x = \frac{-5 \pm \sqrt{1}}{2 \times 1} \\ x = \frac{-5 \pm 1}{2} \\ \\ x' = \frac{-5 + 1}{2} = \frac{-4}{2} = -2 \\ x'' = \frac{-5 -1}{2} = \frac{-6}{2} = -3$

x = -2, x = -3