Question

x²+5x+4=0 (delta e bhaskara)

Answer 1

Explicação passo-a-passo:

x²+5x+4=0

resposta direta

a= x²

b= +5x formula- (x= -b±√b²-4.a.c/2)

c= +4

X= -5±√5²-4.1.4/2

x= -5±√25-16/2

x= -5±√9/2

x= -5 ± 3/2

x¹= -5+3= -2/2= -1

x= -5-3 = -8/2 = -4

Answer 2

Resposta:

x' = -1

x" = -4

Δ = b² - 4 * a * c = 3

Explicação passo-a-passo:

a = 1

b = 5

c = 4

$x =\frac{-b +-\sqrt{b^{2} - 4 *a*c} }{2*a}$

$x = \frac{-(5) +- \sqrt{(5)^{2} - 4 * 1 * 4} }{2*1}$

$x = \frac{-5+-\sqrt{25-16} }{2}$

$x = \frac{-5 + -\sqrt{9} }{2}$

$x' = \frac{-5 +3}{2} = \frac{-2}{2} = -1$

$x" = \frac{-5 -3}{2} = \frac{-8}{2} = -4$