Question

x2 + 4x - 77 = 0 alguemmm me ajuda urgente pf

Answer 1

Utilizando a fórmula de Bháskara.

$x^2+4x-77=0$

Coeficientes: a = 1, b = 4 e c = -77.

$\Delta=b^2-4ac\\\Delta=4^2-4.1.(-77)\\\Delta=16+308\\\Delta=324$

$x=\frac{-b+-\sqrt{\Delta}}{2a}\\\\x=\frac{-4+-\sqrt{324}}{2.1}\\\\x=\frac{-4+-18}{2}\\\\x_1=\frac{-4+18}{2}=\frac{14}{2}=7\\\\x_2=\frac{-4-18}{2}=\frac{-22}{2}=-11$


Espero ter ajudado.
Bons estudos! :)