Question

X2+4x-5=0 de bhaskara

Answer 1

${x}^{2} + 4x - 5 = 0$

$x1 = \frac{ - 4 + \sqrt{ {4}^{2} - 4 \times 1 \times ( - 5) } }{2 \times 1}$

$x1 = \frac{ - 4 + \sqrt{36} }{2}$

$x1 = \frac{ - 4 + 6}{2}$

$x1 = \frac{2}{2} = 1$

$x2 = \frac{ - 4 - \sqrt{36} }{2}$

$x2 = \frac{ - 4 - 6}{2}$

$x2 = \frac{ - 10}{2} = - 5$