Question

x²+4x-12=0 sem usar baskara

Answer 1

Olá :

Resolução :

$x^2 + 4x - 12 = 0 \\ \\ x^2 + 4x + 2^2 = 12 + 2^2 \\ \\ x^2 + 4x + 4 = 12 + 4 \\ \\ x^2 + 4x + 4 = 16 \\ \\ (x + 2)^2 = 16 \\ \\ x + 2 = \pm ~~\sqrt{16} \\ \\ x + 2 = \pm~~4 \\ \\ x = - 2~~\pm~~ 4 \\ \\ \\ x' = -2 + 4 = 2 \\ \\ x'' = - 2 - 4 = - 6 \\ \\ S = \{-6,2\}$

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