Question

x2-4x-12=0 ajudem pfv

Answer 1

x²-4x-12=0

∆= (-4)²-4.1.(-12)
∆= 16 +48
∆=64

x= -(-4)±√64/2.1
x= 4±8/2
x1= 4+8/2=12/2=6
x2= 4-8/2= -4/2=-2
S={6,-2}