Question

X2-4×+5=0 numeros complexos

Answer 1

x² - 4x + 5 = 0

a = 1, b = - 4, c = 5

Δ = b² - 4ac

Δ = (- 4)² - 4·(1)·(5)

Δ = 16 - 20

Δ = - 4

x = - b ± √Δ / 2a

x = - (- 4) ± √(- 4) / 2·(1)

x = 4 ± 2i / 2

x' = 4 + 2i / 2 = 2 (2 + i) / 2 = 2 + i

x'' = 4 - 2i / 2 = 2 (2 - i) / 2 = 2 - i