Question

x² + 3x - 10 =0 .
2 e solucao dessa equacao?

Answer 1

x² +3x -10 = 0
∆ = 3² - 4. 1. (-10)
∆ = 9 + 40
∆ = 49

Bhaskara = -3 ± 7/2
x' = 4/2 = 2
x" = -10/2 = -5

espero ter ajudado!!

Answer 2

$x^{2}+3x-10=0$
$x^{2}+3x=10$
$x^{2}+3x+\frac{9}{4}=10+\frac{9}{4}$
$(x+\frac{3}{2})^{2}=\frac{49}{4}$
$x+\frac{3}{2}=+-\frac{7}{2}$
$x=+-\frac{7}{2}-\frac{3}{2}$

Então,
 $x=\frac{7}{2}-\frac{3}{2}=\frac{5}{2}$
ou
$x=-\frac{7}{2}-\frac{3}{2}=\frac{-10}{2}=-5$

X= $\frac{5}{2}$ ou $X= -5$