Question

x²-3/4x+1/8=0 alguém me ajuda?​

Answer 1

Explicação passo-a-passo:

$x^{2}-\frac{3}{4}x+\frac{1}{8}=0$

usando a fórmula quadrática, fica

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

$x=\frac{-(-\frac{3}{4})+/-\sqrt{(\frac{3}{4})^{2}-4.1.\frac{1}{8}}}{2.1}$

$x=\frac{\frac{3}{4}+/-\sqrt{\frac{9}{16}-\frac{4}{8}}}{2}$

$x=\frac{\frac{3}{4}+/-\sqrt{\frac{9-8}{16}}}{2}$

$x=\frac{\frac{3}{4}+/-\sqrt{\frac{1}{16}}}{2}$

$x=\frac{3}{4}$±$\frac{1}{4}$

    $x_{1}=\frac{\frac{3}{4}+\frac{1}{4}}{2}$

    $x_{1}=\frac{\frac{4}{4}}{2}$

    $x_{1}=\frac{1}{2}$

    $x_{2}=\frac{\frac{3}{4}-\frac{1}{4}}{2}$

    $x_{2}=\frac{\frac{2}{4}}{2}$

    $x_{2}=\frac{2}{4}.\frac{1}{2}$

    $x_{2}=\frac{1}{4}$