Question

- x² - 2x + 1, posso resolver se delta não for uma raiz exata

Answer 1

$-x^2-2x+1=0\\\\ \begin{cases}a=-1\\ b=-2\\ c=1\end{cases}$

$\Delta=b^2-4ac\\ \Delta=(-2)^2-4\cdot(-1)\cdot1\\ \Delta=4+4\\ \Delta=8$

$x= \dfrac{-b\pm \sqrt{\Delta} }{2a}\\\\ x= \dfrac{-(-2)\pm \sqrt{8} }{2\cdot(-1)}= \dfrac{2\pm \sqrt{2^2\cdot2} }{2}= \dfrac{\not2^1\pm\not2 \sqrt{2} }{\not2}=1\pm \sqrt{2}\\\\\\ \Large\boxed{S=\{1\pm \sqrt{2} \} }$

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