Question

-x2+28x-75=0 baskhara

Answer 1

$\mathsf{\purple{Vamos~l\acute{a}!!!}}$

Para resolvermos uma $\mathsf{\green{equac_{\!\!\!,}\tilde{a}o~do~2^{o}~grau}}$ é preciso achar o valor do $\green{\mathsf{delta}}$, sabendo que $\Rightarrow~\mathsf{\green{\Delta =b^{2}-4ac}}$ com isso você parte para achar os dois valor do $\green{\mathsf{x}}$ sabendo que a equação é $\Rightarrow\mathsf{x=\green{\dfrac{-b\pm\sqrt{\Delta} }{2a} }}$

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$\mathtt{\pink{Resposta:}}$

S { 3 , 25 }

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$\mathtt{\blue{Explicac_{\!\!\!,}\tilde{a}o:}}$

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$\mathsf{\green{-x^{2}+28x-75=0}}$

Sabendo que:

$\boxed{\begin{array}{lr}\mathsf{\green{a}=\red{-1}}\\\\\mathsf{\green{b}=\red{28}}\\\\\mathsf{\green{c}=\red{-75}}\end{array}}$

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$\boxed{\begin{array}{lr}\mathsf{\green{\Delta=b^{2}-4ac}}\\\\\mathsf{\Delta=28^{2}-4\times(-1)\times(-75)}\\\\\mathsf{\Delta=784-300}\\\\\mathsf{\Delta=\red{484}}\end{array}}$

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Após isso resolvermos o valor do $\mathsf{\green{x}}$

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$\boxed{\begin{array}{lr}\mathsf{\green{x=\dfrac{-b\pm\sqrt{\Delta} }{2a} }}\\\\\\\mathsf{x=\dfrac{-28\pm\sqrt{484} }{2\times(-1)} }\\\\\\\mathsf{x=\dfrac{-28\pm22 }{-2}}\end{array}}$

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$\mathsf{x^{I}=\red{3}}$

$\mathsf{x^{II}=\red{25}}$

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$\overline{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~}$

$\boxed{\mathtt{Ass:\color{lime}~~\diagup\!\!\!\!T~~\diagup\!\!\!\!O~~\diagup\!\!\!\!D~~\diagup\!\!\!\!D~~\diagup\!\!\!\!Y~~}\maltese}$

$\underline{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~}$

Answer 2

Resposta:

Explicação passo a passo:

-x^2+28x-75=0 (-1)

x²-28x+75=0

a=1; b =-28; c =75

∆= b²-4ac

∆= (-28)²-4.1.75

∆= 784-300

∆= 484

√∆=22

x= (-b+/- √∆)/2a

x= [-(-28)+/- 22]/2.1

x'=[28+22]/2=50/2= '25'

x"=[28-22]/2= 6/2 = '3'