Question

x²-2+1=0 ( baskara )​

Answer 1

Resposta:

x²-2+1=0

x²-1=0

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-0x-1=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=0~e~c=-1\\\\\Delta=(b)^{2}-4(a)(c)=(0)^{2}-4(1)(-1)=0-(-4)=4\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(0)-\sqrt{4}}{2(1)}=\frac{0-2}{2}=\frac{-2}{2}=-1\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(0)+\sqrt{4}}{2(1)}=\frac{0+2}{2}=\frac{2}{2}=1\\\\S=\{-1,~1\}$