Question

X²-13x+12=0 como resolvo ?

Answer 1

Resolva pela fórmula de báskara
x^2-13x+12=0
delta=b^2-4ac
delta=(-13)^2-4.1.12
delta=169-48
delta=121
x=-b-/+ raiz de delta/2a
x=-(-13)-11/2.1
x=13-11/2
x=2/2
x=1
x=-(-13)+11/2.1
x=13+11/2
x=24/2
x=12

Answer 2

x² - 13x + 12 = 0
a = 1; b = - 13; c = 12

Δ = b² - 4ac
Δ = (-13)² - 4.1.12
Δ = 169 - 48
Δ = 121

x = - b +/- √Δ = - (-13) +/- √121
           2a                2.1

x = 13 + 11 = 24/2 = 12
           2

x = 13 - 11 = 2/2 = 1
          2

R.: x = 1 e x = 12