Question

-x²+12x-20=0 alguem me ajuda?

Answer 1

-x²+12x-20=0
∆=b²-4ac
∆=12²-4.(-1).(-20)
∆=144-80
∆=64
x=-b±√∆/2a
x=-12-8/2.(-1)
x=-20/-2
x=10
x=-12+8/2.(-1)
x=-4/-2
x=2
A={(2 ; 10)}