Question

-x2+×+12=0 ajudeeem pfvvv 2grau

Answer 1

-x² + x + 12 = 0

Δ = 1² - 4(-1)(12)
Δ = 1 + 48
Δ = 49

$x = \frac{-1~\pm~7}{-2} \\ \\ x' = 4 \\ x'' = -3$


S = {-3, 4}