Question

-x²+10x-25>0 equação 2°grau

 

Answer 1

$-x^{2} +10x-25=0= delta b^{2} -4.a.c= delta= 10^{2}-4.(-1).(-25)= delta=100-100=0 x1=10-+ \sqrt{0} /2 x2=10-+ \sqrt{0} /2$