Question

x2 -10x+25=0 com a fórmula de baskhara

Answer 1

Boa tarde

x² - 10x + 25 = 0 

4x² - 40x + 100 = 0
4x² - 40x = -100
4x² - 40x + 100 = 100 - 100
(2x - 10)² = 0
2x - 10 = 0
2x = 10
x = 10/2 = 5 

Answer 2

x² - 10x + 25 =0

a=1
b=-10
c=25

Δ=b²-4ac
Δ=(-10)²-4(1)(25)
Δ=100-100
Δ=0

$x= \frac{-b\pm \sqrt{\Delta} }{2a} =~~ \frac{-(-10)\pm \sqrt{0} }{2} = \frac{10\pm0}{2} \\ \\ x'=x"= \frac{10}{2} =5 \\ \\ S=\{5\}$