Question

x ( x + 3 ) - 40 = 0 "Faça utilizando a formula de Bhaskara"

Answer 1

Explicação passo-a-passo:

$x(x + 3) - 40 = 0$

${x}^{2} + 3x - 40 = 0$

...

$d = {b}^{2} - 4ac$

$d = {3}^{2} - 4 \times 1 \times ( - 40)$

$d = 9 + 160$

$d = 169$

.....

$x = \frac{ - b \frac{ + }{ - } \sqrt{d} }{2a}$

$x = \frac{ - 3 \frac{ + }{ - } \sqrt{169} }{2 \times 1}$

$x = \frac{ - 3 \frac{ + }{ - } 13}{2}$

${x}^{1} = \frac{ - 3 + 9}{2} = \frac{6}{2} = 3$

${x}^{2} = \frac{ - 3 - 9}{2} = \frac{ - 12}{2} = - 6$