Question

x
$x {}^{2} - 5x + 6 = 0$
x2−5x+6=0​

Answer 1

Resposta:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-5x+6=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-5~e~c=6\\\\\Delta=(b)^{2}-4(a)(c)=(-5)^{2}-4(1)(6)=25-(24)=1\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-5)-\sqrt{1}}{2(1)}=\frac{5-1}{2}=\frac{4}{2}=2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-5)+\sqrt{1}}{2(1)}=\frac{5+1}{2}=\frac{6}{2}=3\\\\S=\{2,~3\}$

Answer 2

Resposta:

Para resolver equações do segundo grau utiliza-se a fórmula de Bhaskara.

Δ=$(b)^{2}$-4.a.c

Δ=(-5)-4.1.6

Δ=1

x= $\frac{-b^{2}\sqrt{delta}}{2.a}$

x= $\frac{-(-5)±\sqrt{1}}{2}$

$x_{1} =$$\frac{5+1}{2} =3$

$x^{2} = \frac{5-1}{2}=4$

Solução={2,3}