Question

X elevado ao quadrado menos 8x mais 12 igual a zero

Answer 1

x^2 - 8x + 12 = 0

a = 1
b = - 8
c = 12

Delta = b^2 - 4.a.c
Delta = (- 8)^2 - 4.1.12
Delta = 64 - 48
Delta = 16

x = - b +- VDelta / 2.a
x = - (- 8) +- V16 / 2.1
x = 8 +- 4 / 2

x' = 8 - 4 / 2
x' = 4 / 2
x' = 2

x" = 8 + 4 / 2
x" = 12 / 2
x" = 6

S = { 2, 6 }

Answer 2

$x^{2}$ - 8x + 12=0
Δ=$b^{2}$ - 4.a.c
Δ=$(-8)^{2}$ - 4.1.12
Δ=64-48

x=$\frac{-b + ou - \sqrt{} }{2.a}$=16
x=$\frac{-(-8) + ou - \sqrt{16} }{2.1}$
x=$\frac{8 + ou - 4}{2}$

x'=$\frac{8+4}{2}$= $\frac{12}{2}$=6

x"=[tex] \frac{8-4}{2}= \frac{4}{2} = 2

S={6,2}